70 lines
2.2 KiB
Python
70 lines
2.2 KiB
Python
#!/usr/bin/env python3
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"""检查 user_dashou 中有 user_id 的记录"""
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import re
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with open('xaio_cheng_xu_backup.sql', 'r', encoding='utf-8') as f:
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content = f.read()
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pattern = re.compile(r"INSERT\s+INTO\s+`user_dashou`\s+VALUES\s*\((.+?)\)\s*;", re.IGNORECASE | re.DOTALL)
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matches = list(pattern.finditer(content))
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# 找有 user_id 的记录
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has_uid = 0
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no_uid = 0
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uid_values = []
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for m in matches:
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v = m.group(1).rstrip()
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if v.endswith('NULL'):
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no_uid += 1
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else:
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has_uid += 1
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# 提取最后一个值（user_id）
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last_comma = v.rfind(',')
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uid_val = v[last_comma+1:].strip()
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uid_values.append(uid_val)
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print(f"有 user_id: {has_uid}, 无 user_id: {no_uid}")
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print(f"user_id 值样本: {uid_values[:10]}")
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# 检查 user_main 中这些 user_id 是否存在
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# user_main 的 id 字段是 vals[1]
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main_pattern = re.compile(r"INSERT\s+INTO\s+`user_main`\s+VALUES\s*\((.+?)\)\s*;", re.IGNORECASE | re.DOTALL)
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main_ids = set()
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for m in main_pattern.finditer(content):
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# 简单提取第二个字段 (id)
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v = m.group(1)
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# 找前几个逗号
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in_q = False
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commas = []
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for i, ch in enumerate(v):
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if ch == "'": in_q = not in_q
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elif ch == ',' and not in_q:
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commas.append(i)
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if len(commas) >= 2: break
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if len(commas) >= 2:
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id_val = v[commas[0]+1:commas[1]].strip()
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main_ids.add(id_val)
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print(f"\nuser_main id 范围: {len(main_ids)} 个")
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matched = sum(1 for uid in uid_values if uid in main_ids)
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print(f"user_dashou user_id 匹配 user_main: {matched}/{len(uid_values)}")
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# 也检查 user_type 分布
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type_pattern = re.compile(r"INSERT\s+INTO\s+`user_main`\s+VALUES\s*\((.+?)\)\s*;", re.IGNORECASE | re.DOTALL)
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type_counts = {}
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for m in type_pattern.finditer(content):
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v = m.group(1)
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# 找第12个字段 (user_type, index 11)
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in_q = False
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commas = []
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for i, ch in enumerate(v):
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if ch == "'": in_q = not in_q
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elif ch == ',' and not in_q:
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commas.append(i)
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if len(commas) >= 12: break
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if len(commas) >= 12:
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type_val = v[commas[10]+1:commas[11]].strip().strip("'")
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type_counts[type_val] = type_counts.get(type_val, 0) + 1
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print(f"\nuser_type 分布: {type_counts}")
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