TermiNexus
f5da836fbb
机械规则 R2/R3/R4/R6/R7/R8/R13 + R16 保守子集，共 86 文件 2127 行。R1（T | t.CPtr）与 R12（while 下标循环）未做，仍列为待办。全量 77/77 顺序回归通过。
55 lines
1.8 KiB
Plaintext
55 lines
1.8 KiB
Plaintext
from stdint import *
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import t, c
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import ctraits
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import stdio
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import testcheck
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# ============================================================
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# FormatStringTest - 格式化字符串回归测试
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# ============================================================
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export def main() -> int:
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testcheck.begin("FormatStringTest: Format String Regression")
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b: str = "hello world"
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for i in b:
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stdio.printf("%c\n", i)
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b += 1
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print(b-11)
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l: t.CArray[u64] = [0, 43, 2, 3, 4]
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l[0] = 1000
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for i in l:
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stdio.printf("%llu\n", i)
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print("Value: ", f"0x{ULONGLONG(0x11)}")
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print("ULL Hex: ", f"0x{ULONGLONG(0x11):016X}")
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print("LL Hex: ", f"{LONGLONG(0x11):016X}")
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print("ULL Dec: ", f"{ULONGLONG(42):d}")
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print("LL Dec: ", f"{LONGLONG(42):d}")
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print("Hex: ", f"{0x11:016X}")
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print("Dec: ", f"{42:d}")
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print("Float: ", f"{3.14159:.2f}")
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# f-string 赋值测试（验证不再直接 printf，而是生成字符串）
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s: str = f"Value=0x{ULONGLONG(42)}, Hex=0x{ULONGLONG(0x11):016X}"
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print("Assigned: ", s)
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# ctraits.isptr 编译时类型判断测试
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# c.Addr(s) 取的是局部变量 s（str = i8*）的地址，结果是 i8**（char**）；
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# 与 INTPTR（= t.CInt | t.CPtr，int*，见 includes/stdint.vp）层数与基座都不同，
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# 且指针隐式转换已收紧（层数必须相同）⇒ 注解按实际类型写 str | t.CPtr（= i8**）。
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ptr_var: str | t.CPtr = &s
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val_var: int = 42
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if c.CIf(ctraits.isptr(ptr_var)):
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print("ptr_var is pointer")
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if c.CIf(not ctraits.isptr(val_var)):
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print("val_var is not pointer")
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testcheck.section("placeholder")
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testcheck.ok("testcheck framework ready")
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testcheck.info("placeholder test")
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return testcheck.end()
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