75 lines
2.7 KiB
Python
75 lines
2.7 KiB
Python
import os
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import sys
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def batch_replace(root_dir, old_str, new_str):
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"""
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批量替换指定目录下所有文件的内容和文件名中的指定字符串
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参数:
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root_dir: 根目录路径
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old_str: 要替换的旧字符串
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new_str: 替换后的新字符串
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"""
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# 获取当前脚本的文件名，用于忽略自身
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script_name = os.path.basename(sys.argv[0])
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# 先收集所有文件路径，避免在遍历过程中因文件名变化导致问题
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file_paths = []
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for dirpath, _, filenames in os.walk(root_dir):
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for filename in filenames:
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# 忽略脚本自身
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if filename == script_name:
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continue
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file_paths.append(os.path.join(dirpath, filename))
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# 处理文件内容替换
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for file_path in file_paths:
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try:
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# 尝试以文本模式打开文件并读取内容
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with open(file_path, 'r', encoding='utf-8') as f:
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content = f.read()
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# 如果内容中包含要替换的字符串，则进行替换并写入
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if old_str in content:
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new_content = content.replace(old_str, new_str)
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with open(file_path, 'w', encoding='utf-8') as f:
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f.write(new_content)
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print(f"已替换内容: {file_path}")
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except UnicodeDecodeError:
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# 二进制文件可能会解码失败，跳过处理
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print(f"跳过二进制文件: {file_path}")
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except Exception as e:
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print(f"处理文件内容出错 {file_path}: {str(e)}")
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# 处理文件名替换
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for old_path in file_paths:
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dirname = os.path.dirname(old_path)
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old_filename = os.path.basename(old_path)
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# 如果文件名中包含要替换的字符串，则进行替换
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if old_str in old_filename:
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new_filename = old_filename.replace(old_str, new_str)
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new_path = os.path.join(dirname, new_filename)
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# 避免重名
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if not os.path.exists(new_path):
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os.rename(old_path, new_path)
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print(f"已重命名文件: {old_path} -> {new_path}")
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else:
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print(f"跳过重命名，文件已存在: {new_path}")
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if __name__ == "__main__":
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# 设置要处理的根目录，默认为当前目录
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root_directory = os.getcwd()
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# 要替换的字符串
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old_string = "winvnc"
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new_string = "T2SRFB"
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print(f"开始批量替换: {old_string} -> {new_string}")
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print(f"处理目录: {root_directory}")
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batch_replace(root_directory, old_string, new_string)
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print("批量替换完成")
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